res[i] = stack[stack.length - 1]; // 易错点5：用at(-1)兼容性差，优先用stack.length-1
Number (3): Everything in this space must add up to 3. The answer is 2-2, placed vertically; 1-0, placed vertically.
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// 易错点4：栈空时返回1而非i+1 → 仅i=0时正确，i0时（如i=3）会返回1而非4